Daily Quiz Thread

No to all of you.
George can finish four walls by himself in 8 hours, and he has Joe to help him, so it'll be less than that. If they're taking 6 hours, someone's still slacking.
 
No. In 2 hours, George has finished one wall and Joe hasn't finished any. In four hours, they have not finished the fourth wall.
Hint: The answer includes hours and minutes. You will need to do some math for it ... or find a secondary school student to do it for you.
 
Princess Dustmop said:
No. In 2 hours, George has finished one wall and Joe hasn't finished any. In four hours, they have not finished the fourth wall.
Hint: The answer includes hours and minutes. You will need to do some math for it ... or find a secondary school student to do it for you.
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My brain isn't intelligent enough to figure this out lol.
 
Gem789 said:
My brain isn't intelligent enough to figure this out lol.
Click to expand...

Then can you borrow a kid who's in like year 7 to do it for you? Year 5 or 6 might work ... so maybe it's a primary school child we need; I don't remember when these types of problems were assigned. Too old, and they're on to trigonometry and not looking back.
 
Princess Dustmop said:
Then can you borrow a kid who's in like year 7 to do it for you? Year 5 or 6 might work ... so maybe it's a primary school child we need; I don't remember when these types of problems were assigned. Too old, and they're on to trigonometry and not looking back.
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I'm afraid not lol.I'm hoping someone on the forum will work it out.
 
If anyone does want to see how to do the wall painting problem, I just found the spoiler option, so I'll post it under that:
There are two ways to approach the wall painting problem:
- Walls per hour
- Hours per wall

For walls per hour, we know that Joe finishes a wall in 3 hour, so in one hour, he'll finish 1/3 of a wall. George finishes a wall in 2 hours, so he'll finish 1/2 of a wall in one hour. Together, they will finish 1/3 + 1/2, or 5/6 of a wall in one hour. (1/2=3/6, 1/3=2/6; 3/6+2/6 = 5/6). You can convert this to hours per wall by inverting the fraction ... 5/6 walls/hour -> 6/5 hours/wall. 4 walls at a rate of 6/5 hours per wall is 24/5 hours, or 4 + 4/5 hours, and 1/5 of an hour is 12 minutes, so 4/5 of an hour is 48 minutes. Time for 4 walls = 4 hours + 48 minutes.

For hours per wall, the least common multiple for Joe and George's rates is 6 hours. In 6 hours, Joe finishes 2 walls, and George finishes 3 walls, so together they finish 5 walls in 6 hours. That is 6/5 hours per wall. And as we calculated before, 4 walls at 6/5 hours per wall is 4 hours and 48 minutes.
Posyrose said:
Oh, I can't think of a question. I throw it out to the forum. Does anyone have a great question?
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I could write another math problem ...:sly:
 
I don't understand the explanation to it:doh:🤔. Maths was never my strong point. I just get all confused by numbers. You may as well be speaking in a Foreign language! How I happen to have 3 sons who use complicated Maths every day is anybody's guess! (Son No 1 is an Accountant, Son No 2 is a Chemical Engineer and Son No 3 is doing a Maths Degree!)
 
Wall 1
Hour 1 (J)Hour 1 (J)Hour 1 (G)Hour 1 (G)Hour 1 (G)Hour 2 (J)
Wall 2
Hour 2 (J)Hour 2 (G)Hour 2 (G)Hour 2 (G)Hour 3 (J)Hour 3 (J)
Wall 3
Hour 3 (G)Hour 3 (G)Hour 3 (G)Hour 4 (J)Hour 4 (J)Hour 4 (G)
Wall 4
Hour 4 (G)Hour 4 (G)PartialHour(J)PartialHour(G)
 
Princess Dustmop said:
Wall 1
Hour 1 (J)Hour 1 (J)Hour 1 (G)Hour 1 (G)Hour 1 (G)Hour 2 (J)
Wall 2
Hour 2 (J)Hour 2 (G)Hour 2 (G)Hour 2 (G)Hour 3 (J)Hour 3 (J)
Wall 3
Hour 3 (G)Hour 3 (G)Hour 3 (G)Hour 4 (J)Hour 4 (J)Hour 4 (G)
Wall 4
Hour 4 (G)Hour 4 (G)PartialHour(J)PartialHour(G)
Click to expand...
Wha?
 
I figured it out! Noooo, it's too late to post the answer 😂 My brain hurts 😂 😂 😂

The 'simplified' answer is confusing :blink:
 
Yeah, sorry, it posted before I meant to post ... I tried to fix it, but I think I made it worse, :whistle: .

Let me try again ...
Hour 1:
- Joe paints 1/3 of a wall
- George paints 1/2 of a wall
5/6 walls done
Hour 2:
- Joe paints another 1/3 of a wall
- George finishes the wall he started
1+2/3 walls done (or 5/3 or 10/6)
Hour 3:
- Joe finishes the wall he started
- George paints 1/2 of a third wall
2+1/2 walls done (or 5/2 or 15/6)
Hour 4:
- Joe paints 1/3 of the last wall
- George finishes the third wall
3+1/3 walls done (or 10/3 or 20/6)
2/3 wall left ...
1 hour would result in 5/6 wall, which is too much;
5/6 wall ÷ 1 hour = 2/3 wall ÷ ? hours
-> ? hours = 2/3 wall ÷ 5/6 wall per hour
-> ? = 2/3 ÷ 5/6 = 2/3 x 6/5 = 12/15 = 4/5
-> 4/5 hours * 60 = 48 minutes
(Joe paints 4/15 of a wall and George paints 4/10 of a wall in 48 minutes ... 4/15+4/10 = 8/30+12/30=20/30=2/3)

Total time: 4 hours and 48 minutes
 
I think that makes more sense ... ignore the simplified ... I was trying to something visual, but it doesn't really work with the formatting I was trying, so it just didn't work. That ... and I don't think I know how to do math visually. :xd:
 
Anyways ... new "question" ...

If one has two female guinea pigs that are aged 2 years and 3.5 years. In one year, how many guinea pigs will one have? (Not a math problem.)
 
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